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Rectangular table with consecutive integers using foreach
I'd like to have a rectangular table with integers (like a lottery ticket), let's say 4x9, numbers from 1 to 36.I assumed that it is easy with tikz, two foreach loops. Like this:\foreach \i in...
View ArticleAnswer by Péter Juhász for Rectangular table with consecutive integers using...
\pgfmathprintnumber solves the problem.I really don't know why this is so complicated.
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Answer by Mico for Rectangular table with consecutive integers using foreach
Here's a LuaLaTeX-based solution. It employs two for loops.\documentclass{article}\usepackage{array} % for \extrarowheight length parameter and 'w' column type\usepackage{luacode} % for \luaexec...
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Answer by Ignasi for Rectangular table with consecutive integers using foreach
\documentclass[tikz, border=2mm]{standalone}\begin{document}\begin{tikzpicture}\foreach \i in {0,1,2,...,8}{ \foreach \j [evaluate=\j as \num using int(9*(4-\j)+\i+1)] in {1,2,3,4} \node[fill=blue!15,...
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